The converse of the statement "If $p < q$, then $p -x < q -x"$ is -

Consider the following two statements :
$P :$  lf $7$  is an odd number, then $7$ is divisible by $2.$
$Q :$ If $7$ is a prime number, then $7$ is an odd number.
lf $V_1$ is the truth value of the contrapositive of $P$ and $V_2$ is the truth value of contrapositive of $Q,$ then the ordered pair  $(V_1, V_2)$  equals

The statement $( p \wedge q ) \Rightarrow( p \wedge r )$ is equivalent to.

Which of the following is a statement

$(\sim (\sim p)) \wedge q$ is equal to .........

The Boolean expression $ \sim \left( {p \Rightarrow \left( { \sim q} \right)} \right)$ is equivalent to